Jun 4, 2012 · The discussion revolves around creating a position versus time graph for a driving scenario involving different speeds and a stop. The initial attempt at the graph was incorrect, as it …

Sep 9, 2009 · Homework Statement Three particles move along the x-axis, each starting with v= 10m/s at t_0 = 0s. The graph for A is a position-versus-time graph; the graph for B is a velocity-versus-time …

Sep 27, 2007 · The discussion centers on the position-vs-time graph of an object experiencing a constant negative force, such as a car slowing down. Participants clarify that a negative force can …

May 4, 2017 · 1. A bicyclist has the position-versus-time graph as shown. What is the bicyclist's velocity (in m/s) at t = 5 seconds? 2. Since this is a simple velocity problem, I thought it would be v= 60 m/ 5s …

Dec 9, 2016 · What is the phase constant? Homework Equations x (t) = A*cos (ωt+Φ) The Attempt at a Solution If I'm not mistaken at t = 0 the graph starts at half the amplitude or 5. Also the amplitude of …

Nov 14, 2009 · Homework Statement i am having trouble converting an angular v vs. time to position vs. time graph. i know that the slope of the position is the...

Oct 1, 2008 · To create a position versus time graph for a car moving towards an observer and accelerating, the graph should start at a point representing the car's initial position and curve upward, …

Jan 31, 2012 · To find instantaneous velocity from a position versus time graph, it's essential to draw the tangent line at the specific time points. For t = 3.00 s, the slope of the tangent line should be …

Mar 20, 2016 · So I should do position/time instead of multiplying them together? If you spend one second running from a mark "-16 meter" to a mark "0" 16 meters away, what is the distance you …

Feb 4, 2012 · The discussion centers on estimating instantaneous velocity from a position-versus-time graph of a drag racer. Initially, the estimated velocity at 2.0 seconds was around 50 m/s, but after …